Popular tricks

I want to use function attempt for login authenticate but i don't want send variable password * If i run code this it will show error "Undefined index: password" and this below vendor\laravel\framework\src\Illuminate\Auth\EloquentUserProvider.php public function validateCredentials(UserInterface $user, array $credentials) { $plain = $credentials['password']; return $this->hasher->check($plain, $user->getAuthPassword()); How can i do that . pls thank you

If You're raning Laravel 5.4, You May Get An Error While You'are Migrate Or Dealing with the db . The Error is look like : [Illuminate\Database\QueryException] SQLSTATE[42000]: Syntax error or access violation: 1071 Specified key was too long; max key length is 767 bytes (SQL: alter table users add unique users_email_unique(email)) [PDOException] SQLSTATE[42000]: Syntax error or access violation: 1071 Specified key was too long; max key length is 767 bytes

The following example shows an controller with a method, in which we change some values from the .env. Make sure, the entries you want to change, really exist in your .env. https://github.com/Brotzka/laravel-dotenv-editor

This code snippet overrides DuskTestCase->createBrowsers method to allow HTML elements count assertion

Sometimes you need to use some packages based on the environment in which the application is running in, for example "development". You can append environment service providers and aliases in your development configuration file "app/config/development/app.php" with the "append_config" helper method.

Laravel Load More Data on Page Scroll – Laravel 5

For example, if you are using a caching server which listens on HTTPS, which retrieves your content from another (local server) which isn't using HTTPS, your links might be generated as http://mysite.com instead of the desired https://mysite.com. With this trick you can circumvent this.

There are many tricks to return the response in `json`. Actually, if the returned value is an array or instance of "arrayableinterface" or "jsonableinterface" such as eloquent model, you could just return it, it'll be a json, magically. There are following three way i have noticed performance :) Thanks. #KeepSharing

It's possible to add condition to your model's relationships... Help me to use Eloquent with a legacy database..